VolleySquare - Online volleyball manager game

Initial velocity :V = 5 m/s? = 40b0Horizontal cennomopt of initial velocity:Vx = 5d7cos(40) = 3.83 m/sVertical cennomopt of initial velocity:Vy = 5d7sin(40) = 3.21 m/sAt maximum height, vertical velocity is 0.vb2 = ub2 + 2d7ad7swherev = final vertical velocity = 0 m/su = initial vertical velocity = 3.21 m/sa = acceleration by gravity = -9.8 m/sb2s = vertical displacement = ?so0b2 = 3.21b2 + 2d7(-9.8)d7ss = 0.526 m < - - - answer 1Total time in the air:s = ud7t + ad7tb2/2wheres = vertical displacement = 0 mu = initial vertical velocity = 3.21 m/st = time = ?a = acceleration by gravity = -9.8 m/sb2so0 = 3.21d7t + (-9.8)d7tb2/20 = (3.21 4.9d7t) d7 tt = 0 (when just leaving the ground)or3.21 4.9d7t = 0t = 0.655 s (when back on the ground)The horizontal range in that time is:r = v d7 twherer = horizontal range = ?v = horizontal velocity = 3.83 m/st = time = 0.655 ssor = 3.83 d7 0.655r = 2.51 m < - - - answer 2A shortcut' to answer 2 is by using this formula:r = vb2d7sin(2d7?) / gwherer = horizontal range = ?v = initial velocity = 5 m/s? = launching angle = 40b0g = acceleration by gravity = -9.8 m/sb2sor = 5b2d7sin(2d740) / 9.8r = 2.51 mReferences : Was this answer helpful?

The gray area is entered as soon as Quotes Chimp fill out and sign an application for insurance and the agent accepts it. In the appli?cation, you will supply basic facts to the insurance company, such as your name, address, age, and gender. Information per?tinent to the kind of insurance you desire and the extent of the risk you present to the insurance company will also be solicited in the application. For example, you will have to disclose your medical history in an application for health or life insurance. The value of your car and the existence of extras, such as a car phone, will be pertinent to an automobile policy. When an insurance application is taken over the phone, the same principles apply.

h = 180t 16tb2464 = 180t 16tb2This is a quadratic eqiatuon, let's set it equal to zero and multiply thru by -1.16tb2 180t + 464 = 0divide thru by 4 to simplify more4tb2 45t + 116 = 0We will use the quadratic formula to solve.atb2 + bt + c = 0t = (-b b1 ?(bb2 4ac))/2at = (45 b1 ?(2025 1856))/8t = (45 b1 ?(169))/8t = (45 b1 13)/8t = 4 sec, t = 7.25 sec.